A medium has nv = 1.56, nr=1.44. Then it...

A medium has `n_v = 1.56, n_r=1.44`. Then its dispersive power is:

`3//50`

`6//25`

`0.03`

none of these

Text Solution

Verified by Experts

The correct Answer is:

`omega=(n_(v)-n_(r))/(((n_(v)+n_(r))/(2))-1)=(6)/(25)`

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