A man is standing at the edge of a 1m deep swimming pool, completely filled with a liquid of refractive index `sqrt(3/2)`. The eyes of the man are `sqrt3`m above the ground. A coin located at the bottom of the pool appears to be an angle of depression of `30^@` with reference to the eyes of man. Then horizontal distance (represented by x in the figure) of the coin from the eye of the man is ...........mm.

Answer

`d=4000 mm`

Explanation

`sin 60^(@)=sqrt(3/(2))sinr rArrr=45^(@)`
`therefore S=h=1m`
`y=H tan60^(@)=3m`
`therefore x=S+y=4m=4000mm`