An observer observer a fish moving upwards in a cylindrical container of cross section area `1 m^(2)` filled with water up to a height of `5 m`. A hole is present at the botton of the container having cross section areea `1//1000 m^(2)`. Find out the speed of the image of fish observed by observer when the botton hole is just opened. (Given: The fish is moving with the speed of `6 m//s` towards the observer, `mu` of water `=4//3`)

Answer

`4.4975 rh//s`

Explanation

`V_(2)=sqrt(2gh)`
`A V_(1)=Av_(2) rArr V_(1)=10^(-3)xx10=10^(-2)m//s`
Velocity of fish observed `=((u+V_(1)))/(n)-V_(1)=(6+10^(-2))/(4/3)-0.01=4.4975 m//s`