The refracting angle of a glass prism is `30^@.` A ray is incident onto one of the faces perpendicular to it. Find the angle `delta` between the incident ray and the ray that leaves the prism. The refractive index of glass is `mu=1.5.`

Answer

`theta = 60^(@)`

Explanation

Here `i_(C) = sin^(-1) ((1)/(1.5)) sin^(-1) ((2)/(3)) lt 60^(@)`
So, `T.I.R` takes place at second surface
`theta + 120^(@) = 180^(@), theta = 60^(@)`