A charged particle of mass `5 mg` and charge `q=+2muC` has velocity `vecv=2hati-3hatj+4hatk`. Find out the magnetic force on the charged particle and its acceleration at this instant due to magnetic field `vecB=3hatj-2hatk, vecv` and `vecB` are in `m//s` and `Wb//m^(2)` respectively.

Explanation

`vecF=qvecvxxvecB=(2xx10(2-3)xx4k) = 2xx10^(-5)(-6j+4hati+6hatk)N`
By Newton's law `veca=F/m=(2xx10^(-5))/(5xx10^(-5))(-6hati+4hatj+6hatk)`
`=0.8
(-3hati+2hatj+3hatk)m//s^(2)`