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The magnetic moment of a short dipole is...

The magnetic moment of a short dipole is `1 A m^(2)`.What is the magnitude of the magnetic induction in air at `10 cm` from centre of the dipole on a line making an angle of `30^(@)` from the axis of the dipole?

Text Solution

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The correct Answer is:
A, B, C, D
`B_(P)=(mu_(0))/(4pi)M/d^(3)sqrt(1+3cos^(2)theta)=sqrt13/2xx10^(-4) wb//m^(2)`
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Knowledge Check

  • The magnetic induction at a point on equator of a short magnetic dipole is

    A
    `(pi_(0))/(4pi)(2M)/(r^(3))`
    B
    `(pi_(0))/(4pi) (M)/(r^(3))`
    C
    `(pi_(0))/(4pi)(2M)/(r^(2))`
    D
    `(pi_(0))/(4pi) (M)/(r^(2))`

  • The magnetic induction at any point due to a short magnetic dipole is

    A
    `(pi_(0))/(4pi)(M)/(r^(3))sqrt(3cos^(2)theta+1)`
    B
    `(pi_(0))/(4pi) (2M)/(r^(2))sqrt(3cos^(2)theta+1)`
    C
    `(pi_(0))/(4pi)sqrt(3cos^(2)theta+1)`
    D
    `(pi_(0))/(4pi)(2M)/(r^(3)sqrt(3cos^(2)theta+1))`

  • The magnetic induction at a point on axis of a short magnetic dipole is

    A
    `(pi_(0))/(4pi)(2M)/(r^(3))`
    B
    `(pi_(0))/(4pi)(3M)/(r^(3))1`
    C
    `(pi_(0))/(4pi)(M)/(r^(3))`
    D
    `(pi_(0))/(4pi)(2M^(2))/(r^(3))`

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