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Two short magnet A and B of magnetic dip...

Two short magnet `A` and `B` of magnetic dipole mement `M_(1)` and `M_(2)` respectively are placed as shown.The axis of `A` and the equatorial line of `B` are the same.Find the magnetic force on one magnet due to other.

Text Solution

Verified by Experts

The correct Answer is:
`F=3((mu_(0))/(4pi))(M_(2)M_(1))/r^(4)` , upwards on `M_(1)`
down wards on `M_(2)`
Magnetic field due to magnet `B`:
`B=(mu_(0))/(4pi)M_(2)/r^(3)`
Magnetic force acting on magnet `A`
`F=M_(1)(dB)/(dr)=-3((mu_(0))/(4pi))(M_(1)M_(2))/r^(4)`
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Knowledge Check

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    intersect inside the body of the magnet
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    intersect at neutral points only
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