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A square loop of side a carris a current...

A square loop of side a carris a current `I`. The magnetic field at the centre of the loop is

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The correct Answer is:
A, B
`B=4(mu_(0)i)/(4pid)[cos45^(@)+cos 45^(@)]`
`=4(mu_(0)i)/(4pi1/2)[2xx1/sqrt2] , =2sqrt2(mu_(0)i)/(pia)`into the plane of paper.
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RESONANCE-ELECTRODYNAMICS-Exercise-1 PART-1
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