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A proton describes a circle of radius `1 cm` in a magnetic field of strength `0.10 T`.What would be the radius of the circle described by an deuteron moving with the same speed in the same meagnetic field?

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The correct Answer is:
B, C
`r=(mv)/(qB) rArr (m/q)_(D)=2(m/q)_(P)rArrr_(D)=2r_(P)=2cm`
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RESONANCE-ELECTRODYNAMICS-Exercise-1 PART-1
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