An electron beam passes through a magnetic field of `2xx10^(-3) Wb//m^(2)` and an electric field of `3.2xx10^(4) V//m`, both acting simultaneously.`(vecE_|_vecB_|_vecV)` If the path of electrons remains undeflected calculate the speed of [mass of electron`=9.1xx10^(-31)kg`]?

Answer

A, B, C

Explanation

`F_(E)`
`F_(m)=F_(E)`
`eVB=eE`
`V=E/B=(3.2xx10^(4))/(2xx10^(-3))`
`=16xx10^(6) m//s`
`r=(mV)/(eB)=91/20cm`