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Two parallel wires separated by a distance of 10cm carry currents of 10 A and 40 A along the same direction, Where should a third current be placed so that it experience no magnetic force?

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The correct Answer is:
A, B, C, D
`(mu_(0)i_(1))/(2pix)=F=(mu_(0)i_(2))/(2pi(10-x)) 20/x=80/(10-x)`
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RESONANCE-ELECTRODYNAMICS-Exercise-1 PART-1
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