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A straight , long wire carries a current a current of 20A. Another wire carrying equal current is placed parallel to it. If the force acting on a length of 10cm of the second wire is `2.0 xx 10^-5 N`, what is the separation between them?

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The correct Answer is:
C, D
`(mu_(0)i_(1)i_(2))/(2pid)=F/I`
`rArr=2xx10^(-7)xx(20xx20)/d=2xx10^(-4)=2xx10^(-4) rArr d=40cm`.
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