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A charge Q is spread uniformly over an i...

A charge `Q` is spread uniformly over an insulated ring of radius `R`.What is the magnetic moment of the ring if it is rotated with an angluar velocity `omega` about its axis?

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The correct Answer is:
A, B
`i=Qf=(Qomega)/(2pi)`
`M=ixxpiR^(2)=(QomegaR^(2))/2`
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