A weak acid `HX` has the dissociation constant `1 xx 10^(-5)M`. It forms a salt `NaX` on reaction with alkali. The percentage hydrolysis of `0.1M` solution of `NaX` is

Options

A. `0.0001%`
B. `0.01%`
C. `0.1%`
D. `0.15%`

Explanation

`NaX` is a salt of weak acid and strong base.
:.Hydrolysis constant of `NaX` is `K_(h)=(K_(w))/(K_(a))=(1xx10^(-14))/(10^(-5))=1xx10^(-9)`
For this type of salt ,`K_(h)=Ch^(2)`
`C`=molar concentration
`h`=degree of hydrolysis
` :.1xx10^(-9)=0.1xxh^(2)`
or `h^(2)=(1xx10^(-9))/(0.1)=1xx10^(-4)`
:. percentage hydrolusis of `NaX` salt =`1xx10^(-4)xx100=1xx10^(-2)=0.01%`