What will be the `pH` at the equivalence point during the titration of a `100 mL 0.2 M` solution of `CH_(3)CCONa` with `0.2 M` solution of `HCl`? `K_(a)=2xx10^(-5)`

Options

A. `3-logsqrt(2)`
B. `3+logsqrt(2)`
C. `3-log2`
D. `3+log2`

Explanation

`{:(,CH_(3)COONa,+,HCl,rarr,NaCl,+,CH_(3)COOH),(t=0,20m eq,,20meq.,,,,),(t_(eq),-,,-,,,,20meq):}`
`[CH_(3)COOH]=(20)/(100)=0.1M`
`pH=(1)/(2)[pK_(a)-logC]=(1)/(2)[5-log2+1]=(1)/(2)[6-log2]=3-logsqrt(2)`