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CH(3)-overset(CH(3))overset("| ")unders...

`CH_(3)-overset(CH_(3))overset("| ")underset(CH_(3))underset("| ")"C "-underset(OH)underset("| ")"CH"CH_(3)overset("Conc. "H_(2)SO_(4))rarr "A(predominant)".` A is

A

`(CH_(3))_(3)C-CH=CH_(2)`

B

`(CH_(3))_(2)C=C(CH_(3))_(2)`

C

`CH_(2)=underset(CH_(3))underset(|)(C)-CH_(2)-CH_(2)CH_(3)`

D

none is correct

Text Solution

Verified by Experts

The correct Answer is:
B
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