`CH_(3)CH=CH_(2)underset(125^(@)C,"pressure")overset(CO,H_(2)[CoH(CO)_(4)])rarrunderset(Cu-Zn)overset(H_(2))rarr` product
This represents Oxo method of alcohol synthesis. Product can be.

Options

A. `CH_(3)CH_(2)CH_(2)CH_(2)OH`
B. `overset(CH_(3)-CHCH_(2)OH)overset(" | ")(CH _(3))`
C. Both are true
D. none of the above

Answer

To solve the given problem, we will follow the steps of the Oxo process (hydroformylation) for the synthesis of alcohol from propene (CH₃CH=CH₂) using carbon monoxide (CO) and hydrogen (H₂) in the presence of a catalyst.

### Step-by-Step Solution:

1. **Identify the Reactants:**
- The starting material is propene (CH₃CH=CH₂).
- The reagents used are carbon monoxide (CO) and hydrogen (H₂) along with a catalyst (CoH(CO)₄).

2. **Reaction Conditions:**
- The reaction is carried out at 125°C under pressure.

3. **Mechanism of the Oxo Process:**
- In the presence of the catalyst, CO and H₂ react with the double bond of propene. The double bond (C=C) attacks the carbon atom of CO, leading to the formation of a new carbon-carbon bond.
- This results in the formation of an intermediate compound, which can be represented as:
\[ CH₃CH(CH₂CO) \quad \text{(aldehyde intermediate)} \]

4. **Formation of Aldehyde:**
- The intermediate can rearrange to form an aldehyde. The possible aldehyde formed from propene is butanal (CH₃(CH₂)₂CHO).

5. **Reduction to Alcohol:**
- The aldehyde (butanal) is then subjected to hydrogenation in the presence of a copper-zinc catalyst (Cu-Zn) to reduce it to the corresponding alcohol.
- The product of this reduction is butanol (CH₃(CH₂)₂CH₂OH).

6. **Final Products:**
- The final products of the reaction are:
- Butanal (aldehyde)
- Butanol (alcohol)

### Conclusion:
The products obtained from the Oxo method of alcohol synthesis starting from propene are butanal and butanol.