`A_(2) + 2B_(2) to A_(2)B_(4) and (3)/(2) A_(2) + 2B_(2) to A_(3) B_(4)`
Two substance `A_(2) & B_(2)` are allowed to react completely to from `A_(2)B_(4) & A_(3)B_(4)` mixture of leaving none of the reactants. Using this information calculate the composition of final mixture when mentioned amount of `A_(2) & B_(2)` are taken.
(i) If `(5)/(4)` moles of `A_(2) & 2` moles of `B_(2)` is taken
(ii) If `(7)/(2)` moles of `A_(2) & 6` moles of `B_(2)` is taken
(iii) If 4 moles of `A_(2) & 6` moles of `B_(2)` is taken

Answer

(i) `[A_(3)B_(4)=0.5A_(2)B_(4)=0.5]`
(ii) `[A_(3)B_(4)=1A_(2)B_(4)=2]`
(iii) `[A_(3)B_(4)=2A_(2)B_(4)=1]`