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RCOOH overset(PCl(5))to A underset("Cal...

`RCOOH overset(PCl_(5))to A underset("Calalyst")overset(H_(2))to B underset("Catalyst")overset(H_(2))to C overset(PBr_(3))to D overset(KCN) to E underset(H_(2)O)overset(H^(+))toF`

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To solve the given sequence of reactions starting from a carboxylic acid (RCOOH), we will identify each compound step by step. ### Step 1: Reaction with PCl5 1. **Starting Compound**: RCOOH (Carboxylic Acid) 2. **Reaction**: When RCOOH reacts with PCl5, the hydroxyl (-OH) group is replaced by a chlorine (-Cl) atom. 3. **Product A**: The product formed is RCOCl (Acyl Chloride). ### Step 2: Reduction to Aldehyde ...
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HOCH_(2)CH_(2)CH_(2)-overset(O)overset(||)(C)-OCH_(2)CH_(3) overset(PC C)(to) (A) underset((1 "molar equivalent"))overset(H_(2)C = CHMgBr)(to) (B) overset(NH_(4)Cl//H_(2)O)(to)(C)overset(KOH)underset(H_(2)O)(to)overset(H_(3)O^(o+))(to) underset("Pyridine")overset((CH_(3)-overset(O)overset(||)(C))_(2)O)(to)(D) Product (D) is :

Write the IUPAC name of the following compound. overset(5)(C)H_(3)-overset(4)(C)H_(2)-underset(CH_(3))underset(|)overset(3)(C)H-underset(CH_(3))underset(|)overset(CH_(3))overset (2|)(C)-overset(1)(C)H_(3) overset(1)(C)H_(3)-overset(2)(C)H_(2)-overset(3)(C)H_(2)-overset(4)(C)H_(2)-underset(CH_(3))underset(3|)underset(CH-CH_(3))underset(2|)underset(CH-CH_(3))underset(1|)overset(6)(CH)-overset(6)(C)H_(2)-overset(7)(C)H_(2)-overset(8)(C)H_(2)-overset(9)(C)H_(3)

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