A point charge of ` 2 muC ` is kept fixed at the origin. Another point charge of ` 4 mu C ` is brought from a far point to a distance of 50cm from origin. (a) Calculate the electrostatic potential energy of the two charge system. Another charge of ` 11 muC ` is brought to a point 100 cm from each of the two charges. What is the work done ?

Explanation

To solve the problem step by step, we will break it down into two parts: calculating the electrostatic potential energy of the first two charges and then calculating the work done when the third charge is brought into the system.

### Step 1: Calculate the Electrostatic Potential Energy of the Two Charge System

1. **Identify the Charges and Distance**:
- Charge \( q_1 = 2 \, \mu C = 2 \times 10^{-6} \, C \)
- Charge \( q_2 = 4 \, \mu C = 4 \times 10^{-6} \, C \)
- Distance \( r = 50 \, cm = 0.5 \, m \)
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