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Two infinitely long parallel conducting plates having surface charge densities `+ sigma` and `-sigma` respectively, are seperated by a small distance. The medium between the plates is vacuum. If `epsilon_(0)` is the dielectric permittivity of vacumm, then the electric field in the region between the plates is

A

`0 "volt" m^(-1)`

B

`sigma//2epsilon_(0)"volt"m^(-1)`

C

`sigma//epsilon_(0)"volt"m^(-1)`

D

`z sigma// epsilon_(0)"volt"m^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C

Between the plates i.e. in the region II as shwon in the figure, electric field is given by

`E=1/(2 epsilon_(0)) (sigma-(1)-sigma_(2))=1/(2 epsilon_(0))xx 2 sigma=(sigma)/(epsilon_(0)) Vm^(-1)`
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