Electrical force between two point charge is `200N`, if we increase `10%` charge on one of the charge and and decrease `10%` charge on other then electrical force between them for the same direction becomes.

Options

A. 198 N
B. 100 N
C. 200 N
D. 99 N

Answer

A

Explanation

`F=1/(4 pi epsilon_(0)) (q_(1)q_(2))/(r^(2)), q_(1)^(1)=110/100 q_(1)` and `q_(2)^(1)=90/100q_(2)`