A spherical portion has been removed from a solid sphere having a charge distributed uniformly in its volume as shown in the figure. The electric field inisde the emptied space is

Options

A. zero everywherey
B. non-zero and uniform
C. non-uniform
D. zero only at its centre

Answer

B

Explanation

It is non zero and uniform. It is obtained by using per super position method.
Assuming no cavity `E=(K. rho. 4// 3 p r^(3))/(r^(2))=(K. rho 4 pi .r)/3`
Assuming only charge existing in cavity
`vecE_(r_(2))=(K. rho. 4//3 pir_(2)^(3))/(r_(2)^(2))=(K.rho 4 pi .r_(2))/3`
Net field `vecE_(P)=vecE_(1)-vecE_(2)`
Thus, it is uniform and non zero.