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Two large conducting plates are placed p...

Two large conducting plates are placed parallel to each other with a separation of d between them. An electron starting from rest near one of the plates reaches the other plate in time t. If e is the charge on the electron and m is its mass, then the surface charge density on the inner surface is

A

`(d m e)/(4 pi epsilon_(0)t^(2))`

B

`( d m epsilon_(0)) /(4 pi et^(2))`

C

`(2 d m epsilon_(0))/(et^(2))`

D

None of the above

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The correct Answer is:
To find the surface charge density on the inner surface of the two large conducting plates, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Setup**: - We have two parallel conducting plates separated by a distance \( d \). - An electron starts from rest near one of the plates and reaches the other plate in time \( t \). 2. **Electric Field Between the Plates**: - The surface charge density on one plate is \( +\sigma \) and on the other plate is \( -\sigma \). - The electric field \( E \) between the plates is given by: \[ E = \frac{\sigma}{\epsilon_0} \] - Since there are two plates, the net electric field \( E \) is: \[ E = \frac{\sigma}{\epsilon_0} \] 3. **Force on the Electron**: - The force \( F \) acting on the electron due to the electric field is: \[ F = eE = e \left(\frac{\sigma}{\epsilon_0}\right) \] - The acceleration \( a \) of the electron can be calculated using Newton's second law: \[ a = \frac{F}{m} = \frac{e\sigma}{m\epsilon_0} \] 4. **Using the Equation of Motion**: - The electron travels a distance \( d \) in time \( t \) starting from rest. The equation of motion is: \[ d = ut + \frac{1}{2} a t^2 \] - Since the initial velocity \( u = 0 \), we have: \[ d = \frac{1}{2} a t^2 \] - Substituting the expression for acceleration: \[ d = \frac{1}{2} \left(\frac{e\sigma}{m\epsilon_0}\right) t^2 \] 5. **Solving for Surface Charge Density \( \sigma \)**: - Rearranging the equation to solve for \( \sigma \): \[ d = \frac{e\sigma t^2}{2m\epsilon_0} \] \[ \sigma = \frac{2dm\epsilon_0}{et^2} \] ### Final Result: The surface charge density on the inner surface of the plates is: \[ \sigma = \frac{2dm\epsilon_0}{et^2} \]

To find the surface charge density on the inner surface of the two large conducting plates, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Setup**: - We have two parallel conducting plates separated by a distance \( d \). - An electron starts from rest near one of the plates and reaches the other plate in time \( t \). ...
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