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A bob of a simple pendulum of mass 40gm ...

A bob of a simple pendulum of mass `40gm` with a positive charge `4xx10^(-6)C` is oscillating with a time period `T_(1)`.An electric field of intensity `3.6xx10^(4)N//C` is applied vertically upwards.Now the time period is `T_(2)` the value of `(T_(2))/(T_(1))` is `(g=10//s^(2))`

A

0.16

B

0.64

C

1.25

D

0.8

Text Solution

Verified by Experts

The correct Answer is:
C
`T=2pi sqrt(l/(g_("eff"))`
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