A straight vertical conductor carries a ...

A straight vertical conductor carries a current. At a point `5cm` due north of it, the magnetic induction is founded to be `20muT` due east. The magnetic induction at a point `10cm` east of its will be

`5mu` T north

`10 mu T` north

`5mu `T north

`10 mu `T north

Text Solution

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The correct Answer is:

`B = (mu_0 i)/(2pi r)`

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