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A current of 1A is flowing in the sides ...

A current of 1A is flowing in the sides of equilateral triangle of side `4.5xx10^(-2)m`. The magnetic induction at centroid of the triangle:

A

`4 xx 10^(-5) T`

B

`40T`

C

`0.4 xx 10^(-3) T`

D

`4 xx 10^(-2) T`

Text Solution

Verified by Experts

The correct Answer is:
A

`B = (mu_0 i)/(4pi r) (sin theta_1 + sin theta_2) xx 3`
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NARAYNA-MOVING CHARGES AND MAGNETISM-EXERCISE - 2(C.W) (AMPERE.S CIRCUITAL LAW BIO-SAVART LAW AND ITS APPLICATIONS)
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