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Magnetic induction at the center of a ci...

Magnetic induction at the center of a circular loop carrying a current is `'B'` . If `'A'` is the area of the coil, the magnetic dipole moment of the loop is

A

`(BA^2)/(mu_0 pi)`

B

`(BA sqrtA)/(mu_0)`

C

`(BAsqrtA)/(mu_0 pi)`

D

`(2BA)/(mu_0) sqrt(A/pi)`

Text Solution

Verified by Experts

The correct Answer is:
D
`B = (mu_0i)/(2r)`
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Knowledge Check

  • Magnetic dipole moment of rectangular loop is

    A
    inversely proportional to current in loop
    B
    inversely proportional to area of loop
    C
    parallel to plane of loop and proportional to area of loop
    D
    perpendicular to plane of loop and proportional to area of loop

  • The magnetic moment of a circular coil carrying current is

    A
    Directly proportional to the length of the wire in the coil
    B
    Inversely proportional to the length of the wire in the coil
    C
    Directly proportional to the square of the length of the wire in the coil
    D
    Inversely proportional to the square of the length of the wire in the coil

  • Magnetic induction produced at the center of a circular loop of radius R carrying a current is 'B' The magnetic moment of the loop is

    A
    high susceptibility and low retentivity
    B
    low susceptibility and high retentivity
    C
    low susceptibility and low retentivity
    D
    high susceptibility and high retentivity

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