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Magnetic induction at the center of a ci...

Magnetic induction at the center of a circular loop carrying a current is `'B'` . If `'A'` is the area of the coil, the magnetic dipole moment of the loop is

A

`(BA^2)/(mu_0 pi)`

B

`(BA sqrtA)/(mu_0)`

C

`(BAsqrtA)/(mu_0 pi)`

D

`(2BA)/(mu_0) sqrt(A/pi)`

Text Solution

Verified by Experts

The correct Answer is:
D
`B = (mu_0i)/(2r)`
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