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A voltmeter has range 0 to V with a ser...

A voltmeter has range 0 `to` V with a series resistance R. With a series resistance 2R, the range is 0 `to` V'. The correct relation between v and v' is

A

`V' = 2V`

B

`V' gt 2V`

C

`V' lt 2V`

D

`V' gt gt 2V`

Text Solution

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The correct Answer is:
To solve the problem, we need to establish the relationship between the voltages \( V \) and \( V' \) when the voltmeter is connected with different series resistances. ### Step-by-step Solution: 1. **Understanding the Setup**: - A voltmeter with a range of \( 0 \) to \( V \) has a series resistance \( R \). - When the series resistance is changed to \( 2R \), the new range of the voltmeter is \( 0 \) to \( V' \). 2. **Current Calculation for the First Setup**: - The current \( I \) flowing through the circuit when the voltmeter is connected with resistance \( R \) can be expressed using Ohm's Law: \[ I = \frac{V}{R + R_v} \] - Here, \( R_v \) is the internal resistance of the voltmeter. 3. **Voltage Reading for the First Setup**: - The voltage reading on the voltmeter, \( V \), can be expressed as: \[ V = I \cdot R_v = \frac{V}{R + R_v} \cdot R_v \] 4. **Current Calculation for the Second Setup**: - In the second setup, where the series resistance is \( 2R \), the current \( I' \) can be calculated as: \[ I' = \frac{V'}{2R + R_v} \] 5. **Voltage Reading for the Second Setup**: - The voltage reading on the voltmeter in this case, \( V' \), is given by: \[ V' = I' \cdot R_v = \frac{V'}{2R + R_v} \cdot R_v \] 6. **Setting Up the Equations**: - From the first setup, we have: \[ V = \frac{V \cdot R_v}{R + R_v} \] - From the second setup: \[ V' = \frac{V' \cdot R_v}{2R + R_v} \] 7. **Relating \( V \) and \( V' \)**: - Since both expressions for \( V \) and \( V' \) involve the same \( R_v \), we can set up the relationship: \[ \frac{V}{R + R_v} = \frac{V'}{2R + R_v} \] 8. **Cross Multiplying to Solve for \( V' \)**: - Cross-multiplying gives: \[ V(2R + R_v) = V'(R + R_v) \] - Rearranging this leads to: \[ V' = \frac{V(2R + R_v)}{R + R_v} \] 9. **Simplifying the Expression**: - Further simplification leads us to: \[ V' = 2V \cdot \frac{R + R_v - R_v}{R + R_v} = 2V \cdot \frac{R}{R + R_v} \] 10. **Conclusion**: - Thus, the relationship between \( V \) and \( V' \) can be summarized as: \[ V' = 2V \cdot \frac{R}{R + R_v} \]

To solve the problem, we need to establish the relationship between the voltages \( V \) and \( V' \) when the voltmeter is connected with different series resistances. ### Step-by-step Solution: 1. **Understanding the Setup**: - A voltmeter with a range of \( 0 \) to \( V \) has a series resistance \( R \). - When the series resistance is changed to \( 2R \), the new range of the voltmeter is \( 0 \) to \( V' \). ...
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