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In an ammeter 5% of the main current is ...

In an ammeter `5%` of the main current is passing through the galvanometer. If the resistance of galvanometer is G, then the resistance of shunt S will be

A

19G

B

G/19

C

20G

D

G/20

Text Solution

Verified by Experts

The correct Answer is:
B
`S = (G)/(n-1)`
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