A magnetic needle pivoted through its ce...

A magnetic needle pivoted through its centre of mass and is free to rotate in a plane containing uniform magnetic field `200xx10^(-4)T`. When it is displaced slightly from the equilibrium it makes `2` oscillations per second. If the moment of inertia of the needle about the axis of oscillation is `0.75xx10^-5kg m^(2)` , the magnetic moment of the needle is

0.06J/T

0.03J/T

0.12J/T

0.6J/T

Text Solution

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The correct Answer is:

`f=1/(2pi)sqrt((MB)/I)`

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NARAYNA-MAGNETISM AND MATTER-EXERCISE - 2 (H.W)

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