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A bar magnet having a magnetic moment of...

A bar magnet having a magnetic moment of `2xx10^(4) JT^(-1)` is free to rotate in a horizontal plane. A horizontal magnetic field `B=6xx10^(-4)T` exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction `60^(@)` from the field is

A

12 J

B

6 J

C

2 J

D

0.6 J

Text Solution

Verified by Experts

The correct Answer is:
B
`W=MB(costheta_(1)-costheta_(2))`
= `2xx10^(4)xx6xx10^(-4)(cos0^(@)-cos60^(@))`
= `12xx(1-1/2)`
= 6J
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