A closest distance of approach of an `a` particle travelling with a velocity `V` towards `Al_(13)` nucleus . `d` . The closest distacne of approach of an alpha particle travelling with velocity `4V` toward `Fr_(26)` nucleus is
A closest distance of approach of an "alpha" particle travelling with a velocity "v towards "Al(13)" nucleus is d The closest distance of approach of an alpha particle travelling with velocity 4V towards Fe(26) nucleus is
The closed distance of approach of an alpha- particle travelling with velocity V towards a stationary nucleus is d .For the closest distance to become (d)/(3) towards a stationary nucleus of double of the charge,the velocity of projection of the alpha- particle has to be
Write the expression for distance of closest approach for a alpha -particle.
Calculate the nearest distance of approach of an alpha -particle of energy 2.5 Me V being scattered by a gold nucleus (Z=79).
The distance oif closest approach of an alpha-particle fired towards a nucleus with momentum p is r. What will be the distance of closest approach when the momentum of alpha-particle is 2p ?
The distance of closest approach of an alpha -particle fired at nucleus with momentum p is d. The distence of closest approach when the alpha -particle is fired at same nucleus with momentum 3p will be
When an alpha particle of mass m moving with velocity v bombards on a heavy nucleus of charge Ze, its distance of closest approach form the nucleus depends on m as
