Home
Class 12
PHYSICS
A P-type semiconductor has acceptor leve...

A `P`-type semiconductor has acceptor levels `57 meV` above the valence band. The maximum wavelength of light required to create a hole is (Planck's constant `h=6.6xx10^(-34)J-s`)

A

`57Å`

B

`57xx10^(-3)Å`

C

`217100Å`

D

`11.61xx10^(-33)Å`

Text Solution

Verified by Experts

The correct Answer is:
C
`E=(hc)/(lambda) rArr lambda=(hc)/(E)`
`=(6.6xx10^(-34)xx3xx10^(8))/(57xx10^(-3)xx1.6xx10^(-19))=217100 Å`
Promotional Banner

Topper's Solved these Questions

  • SEMICONDUCTOR ELECTRONICS

    NARAYNA|Exercise EXERCISE -1 (C.W) (JUNCTION DIODE)|5 Videos

  • SEMICONDUCTOR ELECTRONICS

    NARAYNA|Exercise EXERCISE -1 (C.W) (APPLICATION OF JUNCTION DIODE AS RECTIFIER)|2 Videos

  • SEMICONDUCTOR ELECTRONICS

    NARAYNA|Exercise C.U.Q (LOGIC GATES)|21 Videos

  • SEMI CONDUCTOR DEVICES

    NARAYNA|Exercise Level-II (H.W)|36 Videos

  • WAVE OPTICS

    NARAYNA|Exercise Exercise - 4 Polarisation|9 Videos

Similar Questions

Explore conceptually related problems

A p-type semoconductor has acceptor levels 57meV above the valence band. Find the maximum wavelength of light which can create a hole.

A p type semiconductor has acceptor level 30 mev above the valence band what will be the maximum wavelength of light that can create a hole

An n-type semiconductor has donor levels at 500 meV above the valence band, the frequnecy of light required to create a hole is nearly

A p-type semiconductor has acceptor energy level 53meV above the valence band. Find the maximum wavelength of light that can creat a hole. Use h=6.63xx10^(-34)Js, c=3xx10^(8)ms^(-1) .

In a p-type semiconductor the acceptor level is situated 60 m eV above the valence band. The maximum wavelength of light required to produce a hole will be [use hc =12400 eV Å] .

Give the order of the following : Planck's constant ( 6.63xx10^(-34) J-s)

The de - Broglie wavelength of a ball of mass 120 g moving at a speed of "20 m s"^(-1) is (Planck's constant h=6.6xx10^(-34)Js )

If a semiconductor photodiode can detect a photon with a maximum wavelength of 400 nm, then its band gap energy is : Planck's constant h= 6.63 xx 10^(-34) J.s Speed of light c= 3xx10^8 m//s

The momentum of a photon of de Broglie wavelength 5000Å is …………… . [Plank's constant =6.63xx10^(-34)J.s ]

The work function of a metal is 3.3 xx10^(-19)J . The maximum wavelength of th e photons required to eject photoelectrons from the metal is (Take h=6.6xx10^(-34)Js )