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Mass M=1 unit is divided into two parts ...

Mass `M=1` unit is divided into two parts `X` and `(1-X)`. For a given separation the value of `X` for which the gravitational force between them becomes maximum is

A

43832

B

43895

C

1

D

2

Text Solution

Verified by Experts

The correct Answer is:
A
`F=(Gxxm(1-x)mx)/(R^(2))` is maximum when `x=1/2`
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NARAYNA-GRAVITATION-EXERCISE -I (C.W.)
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