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A satellite revolves in a circular orbit...

A satellite revolves in a circular orbit with speed, `V=1/(sqrt(3))V_(e)`. If satellite is suddenly stopped and allowed to fall freely onto the earth, the speed with which it hits the earth's surface is

A

`sqrt(gR)`

B

`sqrt((gR)/3)`

C

`sqrt(2gR)`

D

`sqrt(2/3gR)`

Text Solution

Verified by Experts

The correct Answer is:
D

`V=sqrt(V_(e)^(2)-2V_(0)^(2))`
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NARAYNA-GRAVITATION-EXERCISE -I (C.W.)
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