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Fe^(2+)toFe^(3+)+e^(-), MnO(4)^(-)+5e^(-...

`Fe^(2+)toFe^(3+)+e^(-), MnO_(4)^(-)+5e^(-)toMn^(2+)`, the ratio of stoichiometric coefficient of `Fe^(2+) and MnO_(4)` is:

A

`1:5`

B

`5:1`

C

`2:3`

D

`6:1`

Text Solution

Verified by Experts

The correct Answer is:
B
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In the balanced equation FeS+MnO_(4)^(-)overset(H^(+))rarrFe^(3+)+SO_(4)^(2-)+Mn^(2+) the stoichiometric coefficients of FeS and MnO_(4)^(-) are in the ratio :

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Complete the chemical equations : Fe^(2+) + MnO_4^(-) + H^(+) to

What will be the spontaneous reaction when the following half reactions are combined ? (i) Fe^(3+) + e^(-) to Fe^(2+) , (ii) MnO_(4)^(-) + 8 H^(+) + 5 e^(-) to Mn^(2+) + 4 H_(2) O , (E^(Theta) = + 1.49 V ) What is the value of E_(cell)^(Theta) ?

Read the following passage for the evaluation of E^(@) when different number of electrons are involved. Consider addition of the following half reactions (1) Fe^(3+)(aq)+3e^(-)rarr Fe(s) E_(1)^(@)=0.45V (2) Fe(s)rarr Fe^(2+)(aq)+2e^(-) E_(2)^(@)=-0.04V (3) Fe^(3+)(aq)+e^(-)rarr Fe^(2+)(aq) E_(3)^(@)= ? Because half-reactions (1) and (2) contains a different number of electrons, the net reaction (3) is another half-reaction and E_(3)^(@) can't be obtained simply by adding E_(1)^(@) and E_(3)^(@) . The free - energy changes however, are additive because G is a state function : Delta G_(3)^(@)=Delta G_(1)^(@)+Delta G_(2)^(@) For the reactions (1) MnO_(4)^(-)+8H^(+)+5e^(-)rarr Mn^(2)+4H_(2)O E^(@)=1.51 V (2) MnO_(2)+4H^(+)+2e^(-)rarr Mn^(2+)2H_(2)O E^(@)=1.32 then for the reaction (3) MnO_(4)^(-)+4H^(+)+3e^(-)rarrMnO_(2)+2H_(2)O, E^(@) is

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