In the complex with formula `MCl_(3).4H_(2)O` the co-ordination number of the metal M is six. And there is a no molecule of hydration in it. The volume of 0.1 M `AgNO_(3)` solution needed to precitate the free chloride ions in 200 ml of 0.01 M solution of the complex is

Options

A. 40mL
B. 20mL
C. 60mL
D. 80mL

Answer

B

Explanation

The complex will be `M[(H_(2)O)_(4) Cl_(2)[Cl_(2)` the complex will have free chloride ion concentration of (0.01 M).
`1 Cl^(-) + 1AgNO_(3) to AgCl + NO_(3)^(-)`
` (M_(1)V_(1))/(n_(1)) = (M_(2)V_(2))/(n_(2)) or (0.01 xx 200)/(1) = (0.1 xx V_(2))/(1)`
`V_(2) = mL ]`