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The number of solutions of the equation ...

The number of solutions of the equation `sinx. Sin2x.sin3x. Sin4x.sin5x=0` in `[0,pi]` is equal to

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To find the number of solutions for the equation \( \sin x \cdot \sin 2x \cdot \sin 3x \cdot \sin 4x \cdot \sin 5x = 0 \) in the interval \( [0, \pi] \), we need to determine when each sine function is equal to zero. ### Step-by-Step Solution: 1. **Identify when each sine function is zero:** - For \( \sin x = 0 \): - \( x = 0, \pi \) (within the interval \( [0, \pi] \)) - For \( \sin 2x = 0 \): - \( 2x = n\pi \) where \( n \) is an integer. - Thus, \( x = 0, \frac{\pi}{2}, \pi \) (within the interval \( [0, \pi] \)) - For \( \sin 3x = 0 \): - \( 3x = n\pi \) - Thus, \( x = 0, \frac{\pi}{3}, \frac{2\pi}{3}, \pi \) (within the interval \( [0, \pi] \)) - For \( \sin 4x = 0 \): - \( 4x = n\pi \) - Thus, \( x = 0, \frac{\pi}{4}, \frac{\pi}{2}, \frac{3\pi}{4}, \pi \) (within the interval \( [0, \pi] \)) - For \( \sin 5x = 0 \): - \( 5x = n\pi \) - Thus, \( x = 0, \frac{\pi}{5}, \frac{2\pi}{5}, \frac{3\pi}{5}, \frac{4\pi}{5}, \pi \) (within the interval \( [0, \pi] \)) 2. **Collect all unique solutions:** - From \( \sin x \): \( 0, \pi \) - From \( \sin 2x \): \( 0, \frac{\pi}{2}, \pi \) - From \( \sin 3x \): \( 0, \frac{\pi}{3}, \frac{2\pi}{3}, \pi \) - From \( \sin 4x \): \( 0, \frac{\pi}{4}, \frac{\pi}{2}, \frac{3\pi}{4}, \pi \) - From \( \sin 5x \): \( 0, \frac{\pi}{5}, \frac{2\pi}{5}, \frac{3\pi}{5}, \frac{4\pi}{5}, \pi \) 3. **List all unique values:** - Combining all the values, we have: - \( 0, \frac{\pi}{5}, \frac{\pi}{4}, \frac{\pi}{3}, \frac{2\pi}{5}, \frac{\pi}{2}, \frac{3\pi}{5}, \frac{2\pi}{3}, \frac{3\pi}{4}, \pi \) 4. **Count the unique solutions:** - The unique solutions are: - \( 0, \frac{\pi}{5}, \frac{\pi}{4}, \frac{\pi}{3}, \frac{2\pi}{5}, \frac{\pi}{2}, \frac{3\pi}{5}, \frac{2\pi}{3}, \frac{3\pi}{4}, \pi \) - This gives us a total of **10 unique solutions**. ### Final Answer: The number of solutions of the equation \( \sin x \cdot \sin 2x \cdot \sin 3x \cdot \sin 4x \cdot \sin 5x = 0 \) in the interval \( [0, \pi] \) is **10**.
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