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If (log)(10)[1/(2^x+x-1)]=x[(log)(10)5-1...

If `(log)_(10)[1/(2^x+x-1)]=x[(log)_(10)5-1]` , then `x=` 4 (b) 3 (c) 2 (d) 1

A

4

B

3

C

2

D

1

Text Solution

Verified by Experts

The correct Answer is:
D
R.H.S. = `x=[log_(10) 5-log_(10)10]=x log_(10). 5/10 = log_(10).(1)/2^(x)`
` rArr 1/(2^(x)+x-1)=1/2^(x)`
Therefore ` x - 1 = 0 or x = 1`.
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CENGAGE-LOGARITHM AND ITS PROPERTIES-Exercise (Single)
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