A stone is dropped into a well. If the depth of water below the top be `h` and velocity of sound is `v` then the splash in water is heard after `T` sec. Then:

Options

A. `T=(2h)/(v)`
B. `T=sqrt((2h)/(g))+(h)/(v)`
C. `T=sqrt((2h)/(v))(h)/(g)`
D. `T=sqrt((h)/(2g))+(2h)/(v)`

Answer

B

Explanation

Time taken by stone to go down `t_(1)=sqrt((2h)/(g))`
Time taken by sound to come up `t_(2)=(h)/(v)`
`therefore T=t_(1)+t_(2)=sqrt((2h)/(g))+(h)/(v)`