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A particle is moving in a circle of radi...

A particle is moving in a circle of radius `r` with speed `v` as shown in the figure. The magnitude of change in velocity in moving from `P` to `Q` is

A

2v `cos 40^(@)`

B

`2v sin 40^(@)`

C

`2v cos 20^(@)`

D

`2 v sin 20^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D

`|Deltavecv|=2v sin (theta)/(2)=2v sin (40)/(2)=2v sin 20^(@)`
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