A particle is moving along a circular along a circular path of radius 5 m with a uniform speed `5ms^(-1)`. What will be the average acceleration when the particle completes half revolution?

Options

A. zero
B. `10ms^(-2)`
C. `10pi ms^(-2)`
D. `(10)/(pi)ms^(-2)`

Answer

D

Explanation

`t=(piR)/(v)=(pi5)/(5)=pi sec`
`Deltavecv=(-5hati)-(5hati)=-10hati`
`veca_(avg)=(Deltavecv)/(t)=(-10hati)/(pi)`
`rArr |veca_(avg)|=(10)/(pi)`