A particle is thrown up vertically with a speed `v_(1)` in air . If takes time `t_(1)` in upward journey and `t_(2)(gt t_(1))` in the downward journey and returns to the starting point with a speed `v_(2)`. Then:-

Options

A. `v_(1)=v_(2)`
B. `v_(1)ltv_(2)`
C. `v_(1)gtv_(2)`
D. Data is insufficient

Answer

C

Explanation

There is loss of kinetic energy during the motion so it is clear that `v_(1)fgtv_(2)`