A jet airplance travelling at the speed ...

A jet airplance travelling at the speed of ` 500 km ^(-1)` ejects its products of combustion at the speed of ` 1500 km h^(-1)` relative to the jet plane. What is the speed of the burnt gases with respect to observer on the ground ?

1500 km/h

2000km/h

1000km/h

500km/h

Text Solution

Verified by Experts

The correct Answer is:

`V_("gas,plane")=V_("gas")+V_("plane")`
`V_("gas")=V_("gas,plane")-V_("plane")`
`=1500-500=1000lkm//h`

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