A body is projected upwards with a velocity `u`. It passes through a certain point above the ground after `t_(1)`, Find the time after which the body passes through the same point during the journey.

Options

A. `((u)/(g)-t_(1)^(2))`
B. `2((u)/(g)-t_(1))`
C. `3((u^(2))/(g)-t_(1))`
D. `3((u^(2))/(g^(2))-t_(1))`

Answer

B

Explanation

`t_("max")=(u)/(g)`
`therefore` time for upward journey from this particular point
`=(t_("asc")-t_(1))=[(u)/(g)-t_(1)]`
`therefore "total time"=2[(u)/(g)-t_(1)]`