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In the previous question, the mean veloc...

In the previous question, the mean velocity of the rocket reaching the maximum height is :

A

`100ms^(-1)`

B

`50ms^(-1)`

C

`500ms^(-1)`

D

`25//3ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`"Mean velocity"=("Displacement")/("Total time")=("Total height")/("Total time")`
`=(10,000m)/(20sec)=500 m//s`
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