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A man is walking on a road with a veloci...

A man is walking on a road with a velocity 3kmhr. Suddenly rain starts falling. The velocity of rain is 10km/hr in vertically downward direction. the relative velocity of rain with respect to man is :-

A

`sqrt(13) km//hr`

B

`sqrt(7)km//hr`

C

`sqrt(109) km//hr`

D

13 km/hr.

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The correct Answer is:
To find the relative velocity of rain with respect to the man, we can follow these steps: ### Step 1: Define the velocities - The velocity of the man (Vm) is given as 3 km/hr in the horizontal direction. We can represent this as: \[ \vec{V_m} = 3 \hat{i} \text{ km/hr} \] - The velocity of the rain (Vr) is given as 10 km/hr in the vertical downward direction. We can represent this as: \[ \vec{V_r} = -10 \hat{j} \text{ km/hr} \] ### Step 2: Calculate the relative velocity The relative velocity of the rain with respect to the man (Vr_m) is calculated using the formula: \[ \vec{V_{r/m}} = \vec{V_r} - \vec{V_m} \] Substituting the values: \[ \vec{V_{r/m}} = (-10 \hat{j}) - (3 \hat{i}) = -3 \hat{i} - 10 \hat{j} \text{ km/hr} \] ### Step 3: Find the magnitude of the relative velocity To find the magnitude of the relative velocity vector, we use the Pythagorean theorem: \[ |\vec{V_{r/m}}| = \sqrt{(-3)^2 + (-10)^2} \] Calculating this gives: \[ |\vec{V_{r/m}}| = \sqrt{9 + 100} = \sqrt{109} \text{ km/hr} \] ### Step 4: Conclusion The magnitude of the relative velocity of rain with respect to the man is: \[ |\vec{V_{r/m}}| = \sqrt{109} \text{ km/hr} \] ### Final Answer The relative velocity of rain with respect to the man is \(\sqrt{109} \text{ km/hr}\). ---
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