A boy is runing on the plane road with velocity v with a long hollow tube in his hand. The water is falling vertically downwards with velocity u. At water angle to the verticaly, he must inclined the tube the water drops enter it without touching its sides ?

Options

A. `tan^(-1)((v)/(u))`
B. `sin^(-1)((v)/(u))`
C. `tan^(-1)((u)/(v))`
D. `cos^(-1)((v)/(u))`

Answer

A

Explanation

`vecv_(rm)=vecv_(r)-vecv_(m)`
`rArr vecv_(rm)=-uhatj-vhati`
`rArr tan theta=(v)/(u)`
`rArr theta=tan^(-1)((v)/(u))`