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A body covers one-third of the distance ...

A body covers one-third of the distance with a velocity `v_(1)` the second one-third of the distance with a velocity `v_(2)`, and the last one-third of the distance with a velocity `v_(3)`. The average velocity is:-

A

`(v_(1)+v_(2)+v_(3))/(3)`

B

`(3v_(1)v_(2)v_(3))/(v_(1)v_(2)+v_(2)v_(3)+v_(3)v_(1))`

C

`(v_(1)v_(2)+v_(2)v_(3)+v_(3)v_(1))/(3)`

D

`(v_(1)v_(2)v_(3))/(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the average velocity of a body that covers one-third of the distance with a velocity \( v_1 \), the second one-third with a velocity \( v_2 \), and the last one-third with a velocity \( v_3 \), we can follow these steps: ### Step-by-Step Solution: 1. **Define the Total Distance**: Let the total distance be \( D \). Since the body covers one-third of the distance in each segment, we can express the distance for each segment as: \[ d_1 = d_2 = d_3 = \frac{D}{3} \] 2. **Calculate the Time for Each Segment**: The time taken to cover each segment can be calculated using the formula: \[ t = \frac{\text{distance}}{\text{velocity}} \] Thus, for each segment: - Time for the first segment \( t_1 \): \[ t_1 = \frac{d_1}{v_1} = \frac{\frac{D}{3}}{v_1} = \frac{D}{3v_1} \] - Time for the second segment \( t_2 \): \[ t_2 = \frac{d_2}{v_2} = \frac{\frac{D}{3}}{v_2} = \frac{D}{3v_2} \] - Time for the third segment \( t_3 \): \[ t_3 = \frac{d_3}{v_3} = \frac{\frac{D}{3}}{v_3} = \frac{D}{3v_3} \] 3. **Calculate the Total Time**: The total time \( T \) taken to cover the entire distance \( D \) is the sum of the times for each segment: \[ T = t_1 + t_2 + t_3 = \frac{D}{3v_1} + \frac{D}{3v_2} + \frac{D}{3v_3} \] Factor out \( \frac{D}{3} \): \[ T = \frac{D}{3} \left( \frac{1}{v_1} + \frac{1}{v_2} + \frac{1}{v_3} \right) \] 4. **Calculate the Average Velocity**: The average velocity \( V_{avg} \) is defined as the total displacement divided by the total time: \[ V_{avg} = \frac{\text{Total Distance}}{\text{Total Time}} = \frac{D}{T} \] Substituting \( T \): \[ V_{avg} = \frac{D}{\frac{D}{3} \left( \frac{1}{v_1} + \frac{1}{v_2} + \frac{1}{v_3} \right)} = \frac{3}{\left( \frac{1}{v_1} + \frac{1}{v_2} + \frac{1}{v_3} \right)} \] 5. **Final Result**: The average velocity can also be expressed using the formula for the harmonic mean of the velocities: \[ V_{avg} = \frac{3 v_1 v_2 v_3}{v_1 v_2 + v_2 v_3 + v_3 v_1} \] ### Conclusion: The average velocity of the body is given by: \[ V_{avg} = \frac{3 v_1 v_2 v_3}{v_1 v_2 + v_2 v_3 + v_3 v_1} \]
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